Atbilžu arhīvs Atbilžu arhīvs
№ 26041, Algebra, 10 klase
uzdevums ir faila
Apskaties uzdevumu
<1/1>

angel
angel
angel
3²=x+y
lg(xy)=lg

9=x+y
xy=8

x=9-y

y(9-y)=8
y²-9y+8=0
D=81-32=49
y=(9+7)/2=8 x=9-y=9-8=1
y=(9-7)/2=1 x=9-y=9-1=8

vespertilio
vespertilio
vespertilio
2y-x=1
x=4+y

2y-4-y=1
y=5
x=9

BlackRock
BlackRock
BlackRock
{log3 (x+y)=2
{lg xv + lg y=3lg 2

log3 (x+y)=2
log3 (x+y)= log3 9
x+y=9

lg x + lg y=3lg 2
lg x + lg y=lg 23
lg x*y=lg 8
x*y=8

{x+y=9
{x*y=8
Apskaties risinājumu
<1/1>
№ 26101, Algebra, 10 klase
napiwite polnostju vse rewenie , tam tri primera
Apskaties uzdevumu
<1/1>

snow
snow
snow
1) 2(x+5) > x -4 2x+10>x -4 2x - X > -4-10 X > -14
X pridnalizhit (-14;+∞)
2) D.A . 3x + 4 ≠0 x≠-4/3≠-1 1/3 odin i odna trec
2x²+x-6<=0
D = 1² -4 ·2 ·-6 = 1 + 48 = 49
X1 = (-1-7)/4 = -8/4 = -2
X2 = (-1+7)/4 = 6/4 = 1,5
3) D.A. 1-x≠0 x≠1 x+4≠0 x≠-4
(x+4)/(-x²-3x+4) + (2-2x)/(-x² - 3x +4) > 1
x+4+2-2x>-x²-3x+4 X²+3x-4+x+4+2-2x>0
x²+2x+2>0 D = 2² - 4 ·2 = 4 - 8 = -4 KORNEJ NETU

solinjsh
solinjsh
solinjsh
Smotri fail!
Apskaties risinājumu
<1/1>

mggt
mggt
mggt
1) 2÷x-4 > 1÷x+5

2(x-4) x+5
___ > ____ = 2x-4 > x+5
(x-4) (x+5)

x>9 atbilde. ___.\\\\\ x xE (9;+∞) E - pieder
9
2)
2x2+x-6
______ < = 0 man liekas tu te kko nepareizi esi uzraxstiijis
3x+4

2x2+x-6 <= 3x-4
5x-6 <= 3x-4
2x<=2
x=1 atbilde ja jazime likne,tad ___.\\\\\\> x xE [1;+∞)

3) 1(x+4) 2(x-1)
______ + _____ > (1-x)(x+4)
(1-x)(x+4) (1-x)(x+4)

x+4+2x-2 > x+4-x²-4x
x²+6x-2 > 0
D=36-4*1*(-2)
D=√44 = √4*11 = 2√11
№ 26145, Algebra, 10 klase
Fotka estj pozalujsta pomogite , foto ir ludzu palidziet man :)
Apskaties uzdevumu
<1/1>

vespertilio
vespertilio
vespertilio
Skat. failu.
Apskaties risinājumu
<1/1>

arieta
arieta
arieta
failaa
Apskaties risinājumu
<1/1>
№ 26168, Algebra, 10 klase
√3x²+7x-6lielaks vai vienads 0

hhlady
hhlady
hhlady
√3x²+7x-6lielaks vai vienads 0
3x²+7x-6=0
a=3 b=7 c=-6
D=49+72=121
x1=-7+11 dalīts ar 6=viena trešdaļa
x2=-7-11 dalīts ar 6=-3
D[y]=[no -3 līdz vienai trešdaļai ieskaitot]
būs pareizi. :)


marke
marke
marke
3x^2 - 7x - 6=0
3x^2 - 9x + 2x - 6 = 0
3x(x - 3) + 2(x - 3) = 0
(3x + 2)(x - 3) = 0
vienads 3x + 2 = 0 vai x-3 = 0
x= -2/3 vai x=3
№ 26402, Algebra, 10 klase
atrisināt nevienādību
Apskaties uzdevumu
<1/1>

Kuziņš
Kuziņš
Kuziņš
X²-10x+25>0
D=(-10)2 -4*1*25=100-100=0

X1= 10+√D/2*1=10+0/2=10/2=5
x2= 10-√D/2*1=10-0/2=10/2=5

x pieder (-∞;+∞)

inesuxx
inesuxx
inesuxx
peec dotajiem
a=1, b= -10, c= 25
10 ² -4 *1 *25=100-100=0
X1=10-√0 daliits ar divi = 5
x2 = 10+√0 daliits ar divi =5
paarbaude 5²-10*5 +25 =0

snow
snow
snow
X²-10x+25>0
X² - 10x + 25 = 0
D = 100 - 4 · 1 · 25 = 100 - 100 = 0
x1,2 = 10 ÷ 2 = 5
x pieder (- bezgaliba; + bezgaliba)

vespertilio
vespertilio
vespertilio
pielikumā
Apskaties risinājumu
<1/1>

puuteejaXD
puuteejaXD
puuteejaXD
D=10²-4·1·25=0

tā kā D=O, tad ir tikai viena sakne

x=10÷2=5
№ 26424, Algebra, 10 klase
1istēma x2-y2=7
x2+y2=25
2sistēma x2+xy-y2=11
x-y=2
3sistēma x2-y2=5
xy=6
4sistēma x2+3x-4y=20
x2+6x+y=-5

angel
angel
angel
failā
Apskaties risinājumu
<1/2>
№ 26454, Algebra, 10 klase
Pomogite plz reshitj Fotka estj :)))
Apskaties uzdevumu
<1/1>

arieta
arieta
arieta
v faile
Apskaties risinājumu
<1/1>
№ 26507, Algebra, 10 klase
2x²+3x-14
(x-2)(x+3) i vse eto boljwe 0

catwoman
catwoman
catwoman
2x²+3x-14>0
2x²+3x-14=0
D=9+112=121
x=-3+11/4=2 x=-3-11/4=7
x pieder (-∞;2) apvienojuma (7;+∞)

(x-2)(x+3)>0
x-2>0 x+3>0
x>2 x>-3
x pieder (2;+∞)

angel
angel
angel
2x²+3x-14>0
D=9+112=121
x>(-3+11)/4=2
x<(-3-11)/4=-7
x (-∞;-7)U(2;+∞)

(x-2)(x+3)>0
x>2
x<-3
x (-∞;-3)U(2;+∞)

Lacis
Lacis
Lacis
1.2x²+3x-14=
D=3²-4*2*(-14)=121
x1= -3+11:4=2
x2=-3-11:4=-3,5
2,(x-2)(x+3)=
x²+3x-2x-6
x²+x-6=0
D=1-4*1*(-6)=1+24=25
x1= -1+5:2=2
x2= -1-5:2= -3

Blizko
Blizko
Blizko
2x²+3x-14=0; D=9+112=121
x1=(-3+11)/4=2
x2=(-3-11)/4=-3.5
Otvet: X prinadlezit ot -3,5 do 2 (ne vklju4aja oba zna4enija)

(x-2)(x+3)=0
x=2; x=-3
Otvet: X prinadlezit ot -3 do 2 (ne vklju4aja oba zna4enija)

Zelaju uda4i ;)

snow
snow
snow
2x²+3x -14>0
D = 3²-4*2*-14 = 9 + 112 = 121
X1 = (-3-11)/4 = -3,4
X2 = (-3+11)/4 = 2 xpridnalizhit(-∞;-3,4)U(2;+∞)

(x-2)(x+3) > 0
Budet dva vaianta
1) x-2>0 2) x-2<0
x+3>0 x+3<0

x>2 x<2
x>-3 x<-3
x(-∞;-3)U(2;+∞)
№ 26848, Algebra, 10 klase
Pozalujsta pomogite reshitj foto estj ...
Apskaties uzdevumu
<1/1>

Zance18
Zance18
Zance18
e)
3(5x+x²-ka pakape)=3(2*3-ka pakape)
5x+x²=6
x²+5x-6=0
D=25-4*(-6)=25+24=49
x1=(-5-7)/2=-6
x2=(-5+7)/2=1

18.uzd b
2/3(x pakape)=1,5 (pakape 1/4)
1,5( pakape -x)=1,5(pakape 1/4)
-x=1/4
x=-1/4
19.a
3/4(pakape x)=3/4(pakape -x)
x=-x
x+x=o
2x=0
x=0

c)
3x-7=-(7x-3)
3x+7x=7+3
10x=10
x=1
G)
0.2* 5³/5(pakape x)=25(pakape x)/5²=
(0.2*125)/5 pakape x=25 pakape x/5²=
25/5pakape x=25 pakape x/5²
№ 26878, Algebra, 10 klase
X³+2x²-9x-18=0
x³+6x²-9x-54=0

Rewitj neravenstvo! Uda4i :), eto legko, mne interesno u kovo mozg pawet i vam bonusi pojdut!

Nekit
Nekit
Nekit
x³+2x-9x-18=0
x(x²-9)+2(x²-9)=0
(x²-9)(x+2)=0
(x+3)(x-3)(x+2)=0
1) x=-3 2) x=3 3) x=-2



x³ +6x²-9x-54=0
x(x²-9)+6(x²-9)=0
(x+6)(x+3)(x-3)=0
1) x= -6 2) x= -3 3) x=3

snow
snow
snow
X³+2x²-9x-18=0 x²(x+2) -9(x+2)=0 (x²-9)(x+2)=0
x²=9 x1 = 3 x2 = -3 x3 = -2

x³+6x²-9x-54=0 (x²-9)(x+6)=0 x1=3 x2 = -3 x = -6

P.S. Ja uchus toka vo 9. klase =D


vespertilio
vespertilio
vespertilio
1) x²(x+2)-9(x+2)=0
(x²-9)(x+2)=0
(x-3)(x+3)(x+2)=0
x1=3; x2=-3; x3=-2

2) x²(x+6)-9(x+6)=0
(x²-9)(x+6)=0
(x-3)(x+3)(x+6)=0
x1=3; x2=-3; x3=-6
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