![Atbilžu arhīvs](/images/wnd_title_pic_3.gif) | Atbilžu arhīvs | № 22297, Matemātika, 8 klase Najdite Korni uravnenij: 1)15-(x+3)(x-2)=1-(x-4)^2; 2)z-(z+5)(z-5)=5-(z-5)^2. | | |
| | ![Lexxx92](/profiles/upic_2414.jpg)
![Lexxx92](/images/sch_level_sml_0.gif) Lexxx92 | 1)15-(x+3)(x-2)=1-(x-4)^2 15-x^2+2x-3x+6-1+x^2-8x+16=0 36-9x=0 x=4 2)z-z^2+25-5+z^2-10z+25=0 z+25-5-10z+25=0 9z=45 z=5 | | |
| | ![omnium](/profiles/upic_2093.jpg)
![omnium](/images/sch_level_sml_0.gif) omnium | 1) 15-(x+3)(x-2) = 1-(x-4)^2 15 -x^2 +2x-3x+6 = 1 -x^2 +8x-16 -9x = -36 x=4
2) z-(z+5)(z-5) = 5-(z-5)^2 z -z^2 +5z-5z+25 = 5 -z^2 +10z-25 -9z = -45 z=5 | | |
| | ![pwnage](/profiles/defined_pic_1.gif)
![pwnage](/images/sch_level_sml_0.gif) pwnage | смотри решение в файле. | | |
| | ![labaakaa](/profiles/upic_2261.jpg)
![labaakaa](/images/sch_level_sml_0.gif) labaakaa | 15-(x+3)(x-2)=1-(x-4)^2 15-(x^2-2x-6+3x)=1-(x^2-8x+16) 15-x^2+2x+6-3x=1-x^2+8x-16 15+6+16-1=-x^2+x^2-2x+3x+8x 36=9x x=4
z-(z+5)(z-5)=5-(z-5)^2. z-(z^2-5z+5z-25)=5-(z^2-10z+25) z-z^2+25=5-z^2+10z-25 25+25-5=-z+z^2-z^2+10z 45=9z z=5
:)
| |
| | № 22411, Matemātika, 8 klase =) | | |
| | ![(smoking)](/profiles/upic_1753.jpg)
![(smoking)](/images/sch_level_sml_0.gif) (smoking) | A)3 B)3 C)-3 D)-3 | | |
| | ![≈√vp_idb_insp‰](/profiles/upic_7.jpg)
![≈√vp_idb_insp‰](/images/sch_level_sml_1.gif) ≈√vp_idb_insp‰ | a) 3 b) 3 c) -3 d) -3 | | |
| | ![labaakaa](/profiles/upic_2261.jpg)
![labaakaa](/images/sch_level_sml_0.gif) labaakaa | A= 3 B=3 C=-3 D=-3 | | |
| | ![Сашка](/profiles/upic_2710.jpg)
![Сашка](/images/sch_level_sml_0.gif) Сашка | a)3 b)3 c)-3 d)-3 | | |
| | ![Fludorez](/profiles/upic_2564.jpg)
![Fludorez](/images/sch_level_sml_0.gif) Fludorez | a=3 b=3 c=-3 d=-3 | |
| № 23430, Matemātika, 8 klase kaa apreekini ? piem : x < ½ | | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | x < ½ tad x ir 1.. un zinaams ka 1.2 = 0,5
x < 0,5/1 x < ½ | | |
| | ![robis](/profiles/defined_pic_1.gif)
![robis](/images/sch_level_sml_0.gif) robis | x pieder (-∞;½) | | |
| | ![haha1989](/profiles/defined_pic_1.gif)
![haha1989](/images/sch_level_sml_0.gif) haha1989 | x pieder (-∞;½) | | |
| | ![appendigz](/profiles/upic_3225.jpg)
![appendigz](/images/sch_level_sml_0.gif) appendigz | X e (-∞;0,5) | | |
| | ![podvivert](/profiles/upic_4294.jpg)
![podvivert](/images/sch_level_sml_0.gif) podvivert | x<1/2 => x pieder (-& ; 1/2) ;) viss | |
| № 23446, Matemātika, 8 klase √144 = | | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | √144 =12 jo 12x12=144
Nekas grūts. :P | | |
| | ![shawn666](/profiles/defined_pic_1.gif)
![shawn666](/images/sch_level_sml_0.gif) shawn666 | 12 | | |
| | ![catwoman](/profiles/upic_3383.jpg)
![catwoman](/images/sch_level_sml_0.gif) catwoman | √144=12 | | |
| | ![Gimme](/profiles/upic_1360.jpg)
![Gimme](/images/sch_level_sml_0.gif) Gimme | √144=12
12*12=144 | | |
| | ![PinkShadow](/profiles/defined_pic_2.gif)
![PinkShadow](/images/sch_level_sml_0.gif) PinkShadow | √144 = 12 | | |
| | ![Pipardilliite](/profiles/upic_3789.jpg)
![Pipardilliite](/images/sch_level_sml_0.gif) Pipardilliite | √144=12 | |
| № 23447, Matemātika, 8 klase divi pārdevēji tirgoja plēvi no vienāda liluma ruļļiem. Pirmais pārdevējs pārdeva 17, bet otrais -20 ruļļus. Pie tam pirmais pārdevējs pārdeva par 600 m mazāk plēves nekā otrais pārdevējs. Cik metru plēves pārdeva katrs pārdevējs? :):):):):):) (:(:(:(:(:(: | | |
| | ![karlis](/profiles/upic_4378.jpg)
![karlis](/images/sch_level_sml_0.gif) karlis | Pirmais paardeveejs paardeva 3400m bet otrais 4000 m !! Jo viens rullis ir 200m un ir par 3 rulljiem vairaak kuri kopaa ir 600m gari. | | |
| | ![kašķīte](/profiles/defined_pic_2.gif)
![kašķīte](/images/sch_level_sml_0.gif) kašķīte | Es domāju, ka ir tā:
plēves garums x I pārdevējs 17 ruļļi II pārdevējs 20 ruļļi I pārdevējs 20*x-600
no tā seko, ka 20*x-600=17 x=30.85 m
no tā seko, ka I pārdevējs 30.85*17=524.45m II pārdevējs 30.85*20=617m | | |
| | ![Sergey](/profiles/defined_pic_4.gif)
![Sergey](/images/sch_level_sml_0.gif) Sergey | 20-17=3 -- 600m 1rullis -- 600/3=200m 17*200=3400m - pirmais 20*200=4000m - otrais | | |
| | ![PinkShadow](/profiles/defined_pic_2.gif)
![PinkShadow](/images/sch_level_sml_0.gif) PinkShadow | 20-17=3rulli ir 600 metri... 600dalits3=200 metri 1 rullis..... 17*200=3400m pardeva 1.pardevejs 20*200=4000m pardeva 2.pircejs.... | | |
| | ![Pipardilliite](/profiles/upic_3789.jpg)
![Pipardilliite](/images/sch_level_sml_0.gif) Pipardilliite | 1) 20-17=3 rulli par tik rulliem vairaak pardeva otrais 3 rulli = 600 m 1 rullis = 600÷3 1 rullis = 200 m pirmais pardeveejs = 200·17 pirmais pardeveejs = 3400 m pleves otrais pardeveejs = 200·20 otrais pardeveejs = 4000 m pleves
:) | |
| | № 23640, Matemātika, 8 klase aptrisinat x²-16.? | | |
| | ![siikais05](/profiles/defined_pic_2.gif)
![siikais05](/images/sch_level_sml_0.gif) siikais05 | x=4 x=-4 | | |
| | ![Meiteens](/profiles/defined_pic_2.gif)
![Meiteens](/images/sch_level_sml_0.gif) Meiteens | x²-16 x=+/-4 | | |
| | ![bukss_a](/profiles/upic_4597.jpg)
![bukss_a](/images/sch_level_sml_0.gif) bukss_a | x²-16=0 x²=16 x=√16 x1=4 x2=-4 | | |
| | ![chalis](/profiles/defined_pic_4.gif)
![chalis](/images/sch_level_sml_0.gif) chalis | x²=16 x=+4 x=-4 | | |
| | ![Muksts](/profiles/defined_pic_1.gif)
![Muksts](/images/sch_level_sml_0.gif) Muksts | x²-16=0 x²=16 x1=4 x2=-4 | |
| № 24032, Matemātika, 8 klase Atbrivojies no dalsaknes √¼ | | |
| | ![bukss_a](/profiles/upic_4597.jpg)
![bukss_a](/images/sch_level_sml_0.gif) bukss_a | √¼=½ vajadzetu but ta | | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | √¼ = 1/2 , jo kvadratsakne no 4 ir 2. | | |
| | ![Markoo](/profiles/defined_pic_4.gif)
![Markoo](/images/sch_level_sml_0.gif) Markoo | √¼=½ | | |
| | ![kašķīte](/profiles/defined_pic_2.gif)
![kašķīte](/images/sch_level_sml_0.gif) kašķīte |
¼ ir tas pats, kas 4 pakāpē -1. Četri var izteikt kā (2²) pakāpē -1. Tas nozīmē, ka ir √2-². Uz kvadrātsaknes ir 2, ko parasti neraksta, la iatbrīvotos no kvadrātsaknes -2 izdala ar to divnieku, kas ir uz kvadrātsaknes. Iegūstam, ka √¼ =2 mīnuss pirmajā pakāpē, jeb ½ | | |
| | ![Speechless](/profiles/upic_1929.jpg)
![Speechless](/images/sch_level_sml_1.gif) Speechless | ½ | |
| № 24057, Matemātika, 8 klase (2a+3a)(2b+3b)-kvatradsakne no 400 | | |
| | ![Stasja](/profiles/upic_4412.jpg)
![Stasja](/images/sch_level_sml_0.gif) Stasja | (2a+3a)(2b+3b)- √400 = 5a * 5 b - 20 = 25ab-20 | | |
| | ![murrmulis >.<](/profiles/upic_4488.jpg)
![murrmulis >.<](/images/sch_level_sml_0.gif) murrmulis >.< | (2a+3a)(2b+3b)-√400= 4ab + 6ab + 6ab + 9ab - 20= 25ab - 20 | | |
| | ![shelldy89](/profiles/defined_pic_2.gif)
![shelldy89](/images/sch_level_sml_0.gif) shelldy89 | (2a+3a)(2b+3b)- √400=0 4ab+6ab+6ab+9ab-20=0 25ab=20 ab=20÷25 | | |
| | ![Markoo](/profiles/defined_pic_4.gif)
![Markoo](/images/sch_level_sml_0.gif) Markoo | (2a+3a)(2b+3b)-√400= =4ab+6ab+6ab+9ab--20= =25ab-20 | | |
| | ![kašķīte](/profiles/defined_pic_2.gif)
![kašķīte](/images/sch_level_sml_0.gif) kašķīte | (2a+3a)(2b+3b)-√400=5a*5b-20=5(a-b) -20 | |
| № 24078, Matemātika, 8 klase Если задуманное число увеличить на 4 и результат умножить на задуманное число, получится удвоенный квадрат задуманного числа. Найдите задуманное число | | |
| | ![Stasja](/profiles/upic_4412.jpg)
![Stasja](/images/sch_level_sml_0.gif) Stasja | (х+4)* х = 2х² 2х² = х² + 4х х²- 4х = 0 х (х-4)=0 х1 = 0, х-4=0 х2=4 Ответ: 0 или 4 | | |
| | ![Leschinho](/profiles/upic_3108.jpg)
![Leschinho](/images/sch_level_sml_0.gif) Leschinho | x- задуманное число (x+4)*x=2x² x²+4x-2x²=0 -x²+4x=0 x*(-x+4)=0 x=0 -x+4=0 x=4
Ответ: x=0, x=4 | | |
| | ![Senja](/profiles/defined_pic_4.gif)
![Senja](/images/sch_level_sml_0.gif) Senja | Пусть x - Задуманое число (x+4)X=2x² x²+4x=2x² x²-2x²+4x=0 -x²+4x=0 x(-x+4)=0 x=0 или x=4 | | |
| | ![Arno](/profiles/defined_pic_1.gif)
![Arno](/images/sch_level_sml_0.gif) Arno | Iedomato skaitli apzime ar x un tad veic apreikinus. | | |
| | ![Zjuzja](/profiles/defined_pic_2.gif)
![Zjuzja](/images/sch_level_sml_0.gif) Zjuzja | Ответ: 4. (х+4)·х=2х² (4+4)·4=32 2·4²=32 | |
| | № 24407, Matemātika, 8 klase 3√x-2√y+7√y+2√y= | | |
| | ![Markoo](/profiles/defined_pic_4.gif)
![Markoo](/images/sch_level_sml_0.gif) Markoo | 3√x-2√y+7√y+2√y=3√x+7√y | | |
| | ![flowzy](/profiles/defined_pic_2.gif)
![flowzy](/images/sch_level_sml_0.gif) flowzy | 3√x-2√y+7√y+2√y=3√x +7√y | | |
| | ![Stasja](/profiles/upic_4412.jpg)
![Stasja](/images/sch_level_sml_0.gif) Stasja | 3√x-2√y+7√y+2√y= 3√x + 7√y | | |
| | ![Blizko](/profiles/upic_5488.jpg)
![Blizko](/images/sch_level_sml_2.gif) Blizko | 3√x+7√y | | |
| | ![Garik](/profiles/defined_pic_1.gif)
![Garik](/images/sch_level_sml_0.gif) Garik | √x-2√y+7√y+2√y=√x÷7√y | |
|
|